자바스크립트 리턴 한번만 봐주세요 ㅠ

Question

const request &#61; require(&#34;request&#34;);const cheerio &#61; require(&#34;cheerio&#34;);const axios &#61; require(&#34;axios&#34;);const ic &#61; require(&#34;iconv-lite&#34;) let coma &#61; []; const cocoma &#61; async ()&#61;>{ await axios.get(&#96;https://finance.naver.com/marketindex/exchangeDailyQuote.nhn&#96;, {responseType: &#34;arraybuffer&#34;}) .then(async (data1)&#61;>{ const string &#61; await data1.data; const string1 &#61; ic.decode(string, &#96;EUC-KR&#96;).toString(); const string2 &#61; string1.replace(/(
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|)/gm, &#34;&#34;); const $ &#61; cheerio.load(string2); const data2 &#61; $(&#96;body > div > table > tbody&#96;) data2.each(async (i, node) &#61;>{ const title &#61; $(node).find(&#96;td:nth-child(1)&#96;).text(); await coma.push({ date: $(node).find(&#96;.date&#96;).text(), }) })}) return coma} console.log(cocoma()); 독학으로 공부중이라 ㅠㅠ 이거 리턴을 최종적으로 어떻게 해야 하나요?....도저희... 모르겠습니다..

siva6 · Accepted Answer

cheerio 사용법을 잘 모르겠지만, 이렇게 되기를 원하신건지 모르겠네요. const request &#61; require(&#34;request&#34;); const cheerio &#61; require(&#34;cheerio&#34;); const axios &#61; require(&#34;axios&#34;); const ic &#61; require(&#34;iconv-lite&#34;); const cocoma &#61; async ()&#61;>{ const data1 &#61; await axios.get(&#96;https://finance.naver.com/marketindex/exchangeDailyQuote.nhn&#96;, {responseType: &#34;arraybuffer&#34;}); const string &#61; data1.data; const string1 &#61; ic.decode(string, &#96;EUC-KR&#96;).toString(); const string2 &#61; string1.replace(/(
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|)/gm, &#34;&#34;); const $ &#61; cheerio.load(string2); const data2 &#61; $(&#96;body > div > table > tbody&#96;); const coma &#61; data2.map((i, node) &#61;>{ //const title &#61; $(node).find(&#96;td:nth-child(1)&#96;).text(); return { date: $(node).find(&#96;.date&#96;).text() }; }).get(); return coma; }; (async() &#61;> { console.log(await cocoma()); })();

Tae-woong Kim · Answer

Async 함수는 반환값이 항상 Promise 입니다. 따라서 then 콜백에 체인을 하시거나 내부적으로 Async 함수로 한번 더 감싸셔야합니다.// async 함수의 return 값은 반드시 Promise cocoma().then((result) &#61;> console.log(result)); // or (async () &#61;> { console.log(await cocoma()); })();

Jeonlukas · Answer

감사 합니다 !!

자바스크립트 리턴 한번만 봐주세요 ㅠ

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