JS querySelectorAll 함수에서 not( :index ) 를 사용할 수 있을까요?

Question

안녕하세요, 선배님들.document.querySelectorAll( ) 함수에서 Node 리스트 중, 특정 인덱스를 가진 엘리먼트를 not( ) 으로 제외할 수 있을까요? 예를 들어, 아래의 이미지에서 1번 td와 3번 td를 제외한다고 했을 때 not(index) 형태의 코드를 이용할 수 있는지 궁금합니다. (nth-child 밖에 없는 걸까요?..) 선배님들의 답변 미리 감사드립니다 :)

도뎡 · Answer

자답&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61; nth-child로 해결했습니다!&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;rows[j].querySelectorAll('td:not(:nth-child(n&#43;2):nth-child(-n&#43;3)')&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;&#61;

JS querySelectorAll 함수에서 not( :index ) 를 사용할 수 있을까요?

1개의 답변

#not 목록